## Games 1-5## (order does not matter) | ## Game 6 |

## P(NL wins exactly 3 of 5 games) = C[5,3]·[(1/2)^3]·[(1/2)^2] = [(5·4·3)/(3·2·1)]·(1/8)·(1/4) = (10)·(1/8)·(1/4) = 10/32 = 0.3125 | ## P(NL wins) = 1/2 = 0.5000 |

## Games 1-5## (order does not matter) | ## Game 6 |

## P(AL wins exactly 3 of 5 games) = C[5,3]·[(1/2)^3]·[(1/2)^2] = [(5·4·3)/(3·2·1)]·(1/8)·(1/4) = (10)·(1/8)·(1/4) = 10/32 = 0.3125 | ## P(AL wins) = 1/2 = 0.5000 |

## The probability that the series ends in 6 games = |

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