## Games 1-6## (order does not matter) | ## Game 7 |

## P(NL wins exactly 3 of 6 games) = C[6,3]·[(1/2)^3]·[(1/2)^3] = [(6·5·4)/(3·2·1)]·(1/8)·(1/8) = (20)·(1/8)·(1/8) = 20/64 = 0.3125 | ## P(NL wins) = 1/2 = 0.5000 |

## Games 1-6## (order does not matter) | ## Game 7 |

## P(AL wins exactly 3 of 6 games) = C[6,3]·[(1/2)^3]·[(1/2)^3] = [(6·5·4)/(3·2·1)]·(1/8)·(1/8) = (20)·(1/8)·(1/8) = 20/64 = 0.3125 | ## P(AL wins) = 1/2 = 0.5000 |

## The probability that the series ends in 7 games = |

Return to the analytical solution.

Or return to the original problem.