# of games to win the series | explanation | probability |
1 | The series must take more than 1 game, because the champion must win 4 games. | 0 |
2 | The series must take more than 2 games, because the champion must win 4 games. | 0 |
3 | The series must take more than 3 game, because the champion must win 4 games. | 0 |
4 | In order for the series to end after four games, one team must win the first four games in a row. | (1/2)(1/2)(1/2)(1/2) + (1/2)(1/2)(1/2)(1/2) = 2/16 = 1/8 = 0.1250 |
5 | In order for the series to end in 5 games one team must win exactly 3 out of the first 4 games (in any order) and then win the fifth game. | C(4,3) (1/2)(1/2)(1/2)(1/2)(1/2) + C(4,3) (1/2)(1/2)(1/2)(1/2)(1/2) = 8/32 = 1/4 = 0.2500 |
6 | In order for the series to end in 6 games one team must win exactly 3 out of the first 5 games (in any order) and then win the sixth game. | C(5,3) (1/2)(1/2)(1/2)(1/2)(1/2)(1/2) + C(5,3) (1/2)(1/2)(1/2)(1/2)(1/2)(1/2) = 20/64 = 5/16 = 0.3125 |
7 | In order for the series to end in 7 games one team must win exactly 3 out of the first 6 games (in any order) and then win the seventh game. | C(6,3) (1/2)(1/2)(1/2)(1/2)(1/2)(1/2)(1/2) + C(6,3) (1/2)(1/2)(1/2)(1/2)(1/2)(1/2)(1/2) = 40/128 = 5/16 = 0.3125 |
Now check these answers. Remember, the total probability of all possibilities must equal 1.
As you can see, these numbers do check out. Now we find the expected value, E(x), by multiplying each value by its respective probability and adding them all together:
0 + 0 + 0 + 0.5000 + 1.2500 + 1.8750 + 2.1875 = 5.8125
Thus, by averaging all the trials from your model, you should get something near 5.8125 as your answer.
If you like, you may return to the original problem.
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