## Games 1-4## (order does not matter) | ## Game 5 |

## P(NL wins exactly 3 of 4 games) = C[4,3]·[(1/2)^3]·(1/2) = [(4·3·2)/(3·2·1)]·(1/8)·(1/2) = (4)·(1/8)·(1/2) = 1/4 = 0.2500 | ## P(NL wins) = 1/2 = 0.5000 |

## Games 1-4## (order does not matter) | ## Game 5 |

## P(AL wins exactly 3 of 4 games) = C[4,3]·[(1/2)^3]·(1/2) = [(4·3·2)/(3·2·1)]·(1/8)·(1/2) = (4)·(1/8)·(1/2) = 1/4 = 0.2500 | ## P(AL wins) = 1/2 = 0.5000 |

## The probability that the series ends in 5 games = |

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